Édition du: 10/05/2025 |
|
|
||||||||||
|
|
Chiffres et numération
525 525 + (5 x 2 x 5) = 575 |
|
Addition et soustraction
525 = 3 + 4 + … + 32 |
|
525 = T6 + T7
+ … + T14 |
Somme de neuf nombres triangulaires
consécutifs: |
Avec les puissances
525 = 23² – 2² = 25² –
10² = 41² – 34² |
|
|
Voir Diviseurs, Quantité,
Somme,
Fonctions
arithmétiques
Numération: base, [chiffres] |
Repdigit (Brésilien) |
||
525 2,
[1, 0, 0, 0, 0, 0, 1, 1, 0, 1] 3,
[2, 0, 1, 1, 1, 0] 4,
[2, 0, 0, 3, 1] 5,
[4, 1, 0, 0] 6, [2, 2, 3, 3] 7,
[1, 3, 5, 0] 8,
[1, 0, 1, 5] 9,
[6, 4, 3] 10, [5, 2, 5] 11,
[4, 3, 8] |
12,
[3, 7, 9] 13,
[3, 1, 5] 14,
[2, 9, 7] 15,
[2, 5, 0] 16,
[2, 0, 13] 17,
[1, 13, 15] 18,
[1, 11, 3] 19,
[1, 8, 12] 20,
[1, 6, 5] 21,
[1, 4, 0] |
22,
[1, 1, 19] 23,
[22, 19] 24, [21, 21] 25,
[21, 0] 26,
[20, 5] 27,
[19, 12] 28,
[18, 21] 29,
[18, 3] 30,
[17, 15] 60,
[8, 45] |
24,
[21, 21] 34,
[15, 15] 74,
[7, 7] 104,
[5, 5] 174,
[3, 3] 524,
[1, 1] |
Voir Bases / Brésiliens
Suite |
Voir Haut
de page / Autres
nombres |
Voir |
|
Cette page |
http://villemin.gerard.free.fr/NombDico/N5001000/aaaN500/N525.htm
|